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36n^2-729=0
a = 36; b = 0; c = -729;
Δ = b2-4ac
Δ = 02-4·36·(-729)
Δ = 104976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{104976}=324$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-324}{2*36}=\frac{-324}{72} =-4+1/2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+324}{2*36}=\frac{324}{72} =4+1/2 $
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